SSC CHSL Quant Questions
70 questions on Quantitative Aptitude for SSC CHSL. Each comes with the correct answer and a worked explanation.
- Questions
- 70
- Easy
- 33
- Moderate
- 37
Quant topics
Quant questions with solutions
A shopkeeper buys an article for ₹600 and sells it for ₹660. What is the profit percentage?
- (A)15%
- (B)5%
- (C)10%
- (D)9%
Show answer and explanation
Correct answer: (C) 10%
Profit = selling price − cost price = 660 − 600 = 60. Profit percentage is always calculated on the cost price: 60 ÷ 600 × 100 = 10%.
Shortcut: Profit % = (SP − CP)/CP × 100.
The marked price of a watch is ₹1,000. If a discount of 30% is allowed, what is its selling price?
- (A)₹700
- (B)₹650
- (C)₹970
- (D)₹750
Show answer and explanation
Correct answer: (A) ₹700
Discount = 30% of 1000 = 300. Selling price = marked price − discount = 1000 − 300 = 700. So the watch is sold for ₹700.
Shortcut: SP = MP × (100 − d)/100 = 1000 × 70/100.
What is the simple interest on ₹1,500 at 10% per annum for 2 years?
- (A)₹300
- (B)₹150
- (C)₹1,800
- (D)₹330
Show answer and explanation
Correct answer: (A) ₹300
Simple interest = P × R × T ÷ 100 = 1500 × 10 × 2 ÷ 100 = 300. Therefore the interest earned over 2 years is ₹300.
Shortcut: 1% of 1500 is 15; multiply by 10 × 2 = 20.
Find the compound interest on ₹18,000 at 20% per annum for 2 years, compounded annually.
- (A)₹7,830
- (B)₹7,380
- (C)₹7,920
- (D)₹8,100
Show answer and explanation
Correct answer: (C) ₹7,920
Amount after 2 years = 18000 × (1 + 20/100)² = 25920. Compound interest = amount − principal = 25920 − 18000 = 7920. Note that the simple interest for the same period would be only 7200.
Shortcut: For 2 years, effective rate = 2r + r²/100 = 44% of 18000.
The average of 8 numbers is 34. If one number is removed, the average of the remaining numbers becomes 33. What is the removed number?
- (A)49
- (B)41
- (C)8
- (D)33
Show answer and explanation
Correct answer: (B) 41
Sum of all 8 numbers = 8 × 34 = 272. Sum of the remaining 7 numbers = 7 × 33 = 231. The removed number is the difference: 272 − 231 = 41.
Shortcut: Removed number = old average + (n − 1) × (old average − new average) = 34 + 7 × (1).
Two numbers are in the ratio 5 : 8 and their sum is 65. What is the larger number?
- (A)15
- (B)40
- (C)60
- (D)25
Show answer and explanation
Correct answer: (B) 40
Let the numbers be 5x and 8x. Then 5x + 8x = 65, so 13x = 65 and x = 5. The larger number is 8x = 8 × 5 = 40.
Shortcut: Larger number = 8/13 of 65.
Pooja can complete a piece of work in 6 days and Karan can complete the same work in 12 days. In how many days will they finish it working together?
- (A)4 days
- (B)9 days
- (C)3 days
- (D)6 days
Show answer and explanation
Correct answer: (A) 4 days
Pooja's one-day work = 1/6 and Karan's one-day work = 1/12. Together they do 1/6 + 1/12 = 18/72 = 1/4 of the work per day, so the work is finished in 4 days.
Shortcut: Days together = (a × b)/(a + b) = 72/18 = 4.
A train 250 m long is running at 90 km/h. How much time will it take to cross a pole?
- (A)20 seconds
- (B)3 seconds
- (C)7 seconds
- (D)10 seconds
Show answer and explanation
Correct answer: (D) 10 seconds
Convert the speed to metres per second: 90 × 5/18 = 25 m/s. To cross a pole the train covers its own length, so time = 250 ÷ 25 = 10 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
The perimeter of a square is 28 cm. What is its area?
- (A)64 cm²
- (B)98 cm²
- (C)56 cm²
- (D)49 cm²
Show answer and explanation
Correct answer: (D) 49 cm²
Each side of the square = perimeter ÷ 4 = 28 ÷ 4 = 7 cm. Area of a square = side² = 7 × 7 = 49 cm².
Shortcut: Area = (perimeter/4)².
If 25% of a number is 50, what is 75% of the same number?
- (A)150
- (B)50
- (C)160
- (D)37.5
Show answer and explanation
Correct answer: (A) 150
25% of the number is 50, so the number is 50 × 100 ÷ 25 = 200. Now 75% of 200 = 200 × 75 ÷ 100 = 150. Hence the required value is 150.
Shortcut: Scale directly: 50 × 75/25 = 150.
A shopkeeper buys an article for ₹1,800 and sells it for ₹1,980. What is the profit percentage?
- (A)10%
- (B)5%
- (C)9%
- (D)15%
Show answer and explanation
Correct answer: (A) 10%
Profit = selling price − cost price = 1980 − 1800 = 180. Profit percentage is always calculated on the cost price: 180 ÷ 1800 × 100 = 10%.
Shortcut: Profit % = (SP − CP)/CP × 100.
The marked price of a watch is ₹2,400. If a discount of 10% is allowed, what is its selling price?
- (A)₹2,040
- (B)₹2,160
- (C)₹2,390
- (D)₹2,640
Show answer and explanation
Correct answer: (B) ₹2,160
Discount = 10% of 2400 = 240. Selling price = marked price − discount = 2400 − 240 = 2160. So the watch is sold for ₹2,160.
Shortcut: SP = MP × (100 − d)/100 = 2400 × 90/100.
What is the simple interest on ₹5,500 at 4% per annum for 2 years?
- (A)₹440
- (B)₹5,940
- (C)₹550
- (D)₹660
Show answer and explanation
Correct answer: (A) ₹440
Simple interest = P × R × T ÷ 100 = 5500 × 4 × 2 ÷ 100 = 440. Therefore the interest earned over 2 years is ₹440.
Shortcut: 1% of 5500 is 55; multiply by 4 × 2 = 8.
Find the compound interest on ₹18,000 at 5% per annum for 2 years, compounded annually.
- (A)₹1,755
- (B)₹1,800
- (C)₹1,980
- (D)₹1,845
Show answer and explanation
Correct answer: (D) ₹1,845
Amount after 2 years = 18000 × (1 + 5/100)² = 19845. Compound interest = amount − principal = 19845 − 18000 = 1845. Note that the simple interest for the same period would be only 1800.
Shortcut: For 2 years, effective rate = 2r + r²/100 = 10.25% of 18000.
The average of 11 numbers is 28. If one number is removed, the average of the remaining numbers becomes 26. What is the removed number?
- (A)26
- (B)37
- (C)48
- (D)22
Show answer and explanation
Correct answer: (C) 48
Sum of all 11 numbers = 11 × 28 = 308. Sum of the remaining 10 numbers = 10 × 26 = 260. The removed number is the difference: 308 − 260 = 48.
Shortcut: Removed number = old average + (n − 1) × (old average − new average) = 28 + 10 × (2).
Showing 15 of 70 questions. Start a practice set above to work through the rest.
Frequently asked questions
How many SSC CHSL Quant questions can I practise here?
70 questions — 33 easy and 37 moderate. 15 are shown on this page with answers and explanations, and the practice set draws from all of them.
How should I practise Quant for SSC CHSL?
Read through a few solved questions first to see the method, then take a timed practice set. Afterwards, check which questions you got wrong or spent longest on and redo those before moving on.