SSC MTS Mensuration Questions
4 questions on Mensuration for SSC MTS, including questions from 2024 and 2023 papers. Each comes with the correct answer and a worked explanation.
- Questions
- 4
- Easy
- 2
- Moderate
- 2
Mensuration questions with solutions
The circumference of a circle is 264 cm. What is its area? (Take π = 22/7)
- (A)1764 cm²
- (B)5676 cm²
- (C)5544 cm²
- (D)2772 cm²
Show answer and explanation
Correct answer: (C) 5544 cm²
Circumference = 2πr = 264, so r = 264 × 7 ÷ (2 × 22) = 42 cm. Area = πr² = 22/7 × 42 × 42 = 5544 cm².
Shortcut: With π = 22/7, a circumference of 44k gives radius 7k and area 154k².
The perimeter of a square is 96 cm. What is its area?
- (A)625 cm²
- (B)576 cm²
- (C)600 cm²
- (D)192 cm²
Show answer and explanation
Correct answer: (B) 576 cm²
Each side of the square = perimeter ÷ 4 = 96 ÷ 4 = 24 cm. Area of a square = side² = 24 × 24 = 576 cm².
Shortcut: Area = (perimeter/4)².
The perimeter of a square is 28 cm. What is its area?
- (A)64 cm²
- (B)98 cm²
- (C)28 cm²
- (D)49 cm²
Show answer and explanation
Correct answer: (D) 49 cm²
Each side of the square = perimeter ÷ 4 = 28 ÷ 4 = 7 cm. Area of a square = side² = 7 × 7 = 49 cm².
Shortcut: Area = (perimeter/4)².
The circumference of a circle is 132 cm. What is its area? (Take π = 22/7)
- (A)441 cm²
- (B)2772 cm²
- (C)1452 cm²
- (D)1386 cm²
Show answer and explanation
Correct answer: (D) 1386 cm²
Circumference = 2πr = 132, so r = 132 × 7 ÷ (2 × 22) = 21 cm. Area = πr² = 22/7 × 21 × 21 = 1386 cm².
Shortcut: With π = 22/7, a circumference of 44k gives radius 7k and area 154k².
Frequently asked questions
How many SSC MTS Mensuration questions can I practise here?
4 questions — 2 easy and 2 moderate. 4 are shown on this page with answers and explanations, and the practice set draws from all of them.
How should I practise Mensuration for SSC MTS?
Read through a few solved questions first to see the method, then take a timed practice set. Afterwards, check which questions you got wrong or spent longest on and redo those before moving on.