SSC CGL Average question with solution
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The average of 5 numbers is 45. If one number is removed, the average of the remaining numbers becomes 43. What is the removed number?
- (A)45
- (B)43
- (C)48
- (D)53
Correct answer: (D) 53
Sum of all 5 numbers = 5 × 45 = 225. Sum of the remaining 4 numbers = 4 × 43 = 172. The removed number is the difference: 225 − 172 = 53.
Shortcut: Removed number = old average + (n − 1) × (old average − new average) = 45 + 4 × (2).
About this question
- Subject
- Quantitative Aptitude
- Topic
- Average
- Exam
- SSC CGL
- Attempts on SSC Rank
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Last reviewed on 5 Oct 2026. Spotted a mistake? See our correction policy.