SSC CGL Quant Questions
247 questions on Quantitative Aptitude for SSC CGL. Each comes with the correct answer and a worked explanation.
- Questions
- 247
- Easy
- 114
- Moderate
- 158
Quant topics
Quant questions with solutions
If 40% of a number is 280, what is 35% of the same number?
- (A)280
- (B)98
- (C)210
- (D)245
Show answer and explanation
Correct answer: (D) 245
40% of the number is 280, so the number is 280 × 100 ÷ 40 = 700. Now 35% of 700 = 700 × 35 ÷ 100 = 245. Hence the required value is 245.
Shortcut: Scale directly: 280 × 35/40 = 245.
A shopkeeper buys an article for ₹1,600 and sells it for ₹2,080. What is the profit percentage?
- (A)30%
- (B)35%
- (C)25%
- (D)23%
Show answer and explanation
Correct answer: (A) 30%
Profit = selling price − cost price = 2080 − 1600 = 480. Profit percentage is always calculated on the cost price: 480 ÷ 1600 × 100 = 30%.
Shortcut: Profit % = (SP − CP)/CP × 100.
The marked price of a watch is ₹1,700. If a discount of 10% is allowed, what is its selling price?
- (A)₹1,530
- (B)₹1,445
- (C)₹1,870
- (D)₹1,690
Show answer and explanation
Correct answer: (A) ₹1,530
Discount = 10% of 1700 = 170. Selling price = marked price − discount = 1700 − 170 = 1530. So the watch is sold for ₹1,530.
Shortcut: SP = MP × (100 − d)/100 = 1700 × 90/100.
What is the simple interest on ₹6,000 at 12% per annum for 5 years?
- (A)₹3,600
- (B)₹9,600
- (C)₹3,900
- (D)₹2,880
Show answer and explanation
Correct answer: (A) ₹3,600
Simple interest = P × R × T ÷ 100 = 6000 × 12 × 5 ÷ 100 = 3600. Therefore the interest earned over 5 years is ₹3,600.
Shortcut: 1% of 6000 is 60; multiply by 12 × 5 = 60.
The average of 10 numbers is 30. If one number is removed, the average of the remaining numbers becomes 32. What is the removed number?
- (A)12
- (B)32
- (C)2
- (D)30
Show answer and explanation
Correct answer: (A) 12
Sum of all 10 numbers = 10 × 30 = 300. Sum of the remaining 9 numbers = 9 × 32 = 288. The removed number is the difference: 300 − 288 = 12.
Shortcut: Removed number = old average + (n − 1) × (old average − new average) = 30 + 9 × (-2).
Two numbers are in the ratio 3 : 7 and their sum is 140. What is the larger number?
- (A)56
- (B)98
- (C)112
- (D)42
Show answer and explanation
Correct answer: (B) 98
Let the numbers be 3x and 7x. Then 3x + 7x = 140, so 10x = 140 and x = 14. The larger number is 7x = 7 × 14 = 98.
Shortcut: Larger number = 7/10 of 140.
Riya can complete a piece of work in 12 days and Neha can complete the same work in 24 days. In how many days will they finish it working together?
- (A)7 days
- (B)10 days
- (C)12 days
- (D)8 days
Show answer and explanation
Correct answer: (D) 8 days
Riya's one-day work = 1/12 and Neha's one-day work = 1/24. Together they do 1/12 + 1/24 = 36/288 = 1/8 of the work per day, so the work is finished in 8 days.
Shortcut: Days together = (a × b)/(a + b) = 288/36 = 8.
A train 390 m long is running at 108 km/h. How much time will it take to cross a pole?
- (A)17 seconds
- (B)13 seconds
- (C)26 seconds
- (D)10 seconds
Show answer and explanation
Correct answer: (B) 13 seconds
Convert the speed to metres per second: 108 × 5/18 = 30 m/s. To cross a pole the train covers its own length, so time = 390 ÷ 30 = 13 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
The HCF and LCM of two numbers are 11 and 231 respectively. If one of the numbers is 33, what is the other number?
- (A)88
- (B)66
- (C)7
- (D)77
Show answer and explanation
Correct answer: (D) 77
For any two numbers, product of the numbers = HCF × LCM. So the other number = (11 × 231) ÷ 33 = 2541 ÷ 33 = 77.
Shortcut: Other number = HCF × LCM ÷ given number.
If x − 1/x = 11, what is the value of x² + 1/x²?
- (A)121
- (B)123
- (C)22
- (D)119
Show answer and explanation
Correct answer: (B) 123
Squaring both sides: (x − 1/x)² = x² + 1/x² − 2 = 121. Therefore x² + 1/x² = 121 + 2 = 123.
Shortcut: x² + 1/x² = k² + 2 when x − 1/x = k.
The perimeter of a square is 112 cm. What is its area?
- (A)112 cm²
- (B)841 cm²
- (C)224 cm²
- (D)784 cm²
Show answer and explanation
Correct answer: (D) 784 cm²
Each side of the square = perimeter ÷ 4 = 112 ÷ 4 = 28 cm. Area of a square = side² = 28 × 28 = 784 cm².
Shortcut: Area = (perimeter/4)².
The circumference of a circle is 132 cm. What is its area? (Take π = 22/7)
- (A)2772 cm²
- (B)693 cm²
- (C)1386 cm²
- (D)1452 cm²
Show answer and explanation
Correct answer: (C) 1386 cm²
Circumference = 2πr = 132, so r = 132 × 7 ÷ (2 × 22) = 21 cm. Area = πr² = 22/7 × 21 × 21 = 1386 cm².
Shortcut: With π = 22/7, a circumference of 44k gives radius 7k and area 154k².
If 50% of a number is 650, what is 60% of the same number?
- (A)650
- (B)845
- (C)390
- (D)780
Show answer and explanation
Correct answer: (D) 780
50% of the number is 650, so the number is 650 × 100 ÷ 50 = 1300. Now 60% of 1300 = 1300 × 60 ÷ 100 = 780. Hence the required value is 780.
Shortcut: Scale directly: 650 × 60/50 = 780.
The price of an item is first increased by 25% and then decreased by 40%. What is the net percentage change in the price?
- (A)15% decrease
- (B)25% increase
- (C)25% decrease
- (D)5% decrease
Show answer and explanation
Correct answer: (C) 25% decrease
Let the original price be 100. After a 25% increase it becomes 125. A 40% decrease on 125 gives 125 × 60 ÷ 100 = 75. The net change is 75 − 100 = -25, i.e. 25% decrease.
Shortcut: Net % change = a − b − ab/100 = 25 − 40 − 10 = -25%.
A shopkeeper buys an article for ₹600 and sells it for ₹690. What is the profit percentage?
- (A)20%
- (B)15%
- (C)13%
- (D)25%
Show answer and explanation
Correct answer: (B) 15%
Profit = selling price − cost price = 690 − 600 = 90. Profit percentage is always calculated on the cost price: 90 ÷ 600 × 100 = 15%.
Shortcut: Profit % = (SP − CP)/CP × 100.
Showing 15 of 247 questions. Start a practice set above to work through the rest.
Frequently asked questions
How many SSC CGL Quant questions can I practise here?
247 questions — 114 easy and 158 moderate. 15 are shown on this page with answers and explanations, and the practice set draws from all of them.
How should I practise Quant for SSC CGL?
Read through a few solved questions first to see the method, then take a timed practice set. Afterwards, check which questions you got wrong or spent longest on and redo those before moving on.