SSC CGL Average question with solution
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The average of 9 numbers is 49. If one number is removed, the average of the remaining numbers becomes 47. What is the removed number?
- (A)65
- (B)56
- (C)49
- (D)74
Correct answer: (A) 65
Sum of all 9 numbers = 9 × 49 = 441. Sum of the remaining 8 numbers = 8 × 47 = 376. The removed number is the difference: 441 − 376 = 65.
Shortcut: Removed number = old average + (n − 1) × (old average − new average) = 49 + 8 × (2).
About this question
- Subject
- Quantitative Aptitude
- Topic
- Average
- Exam
- SSC CGL
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Last reviewed on 5 Oct 2026. Spotted a mistake? See our correction policy.