SSC CGL Time, Speed and Distance Questions
18 questions on Time, Speed and Distance for SSC CGL, including questions from 2024 papers. Each comes with the correct answer and a worked explanation.
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Time, Speed and Distance questions with solutions
A train 390 m long is running at 108 km/h. How much time will it take to cross a pole?
- (A)17 seconds
- (B)13 seconds
- (C)26 seconds
- (D)10 seconds
Show answer and explanation
Correct answer: (B) 13 seconds
Convert the speed to metres per second: 108 × 5/18 = 30 m/s. To cross a pole the train covers its own length, so time = 390 ÷ 30 = 13 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 750 m long is running at 90 km/h. How much time will it take to cross a pole?
- (A)8 seconds
- (B)27 seconds
- (C)34 seconds
- (D)30 seconds
Show answer and explanation
Correct answer: (D) 30 seconds
Convert the speed to metres per second: 90 × 5/18 = 25 m/s. To cross a pole the train covers its own length, so time = 750 ÷ 25 = 30 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 135 m long is running at 54 km/h. How much time will it take to cross a pole?
- (A)9 seconds
- (B)3 seconds
- (C)18 seconds
- (D)13 seconds
Show answer and explanation
Correct answer: (A) 9 seconds
Convert the speed to metres per second: 54 × 5/18 = 15 m/s. To cross a pole the train covers its own length, so time = 135 ÷ 15 = 9 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 300 m long is running at 36 km/h. How much time will it take to cross a pole?
- (A)60 seconds
- (B)27 seconds
- (C)30 seconds
- (D)34 seconds
Show answer and explanation
Correct answer: (C) 30 seconds
Convert the speed to metres per second: 36 × 5/18 = 10 m/s. To cross a pole the train covers its own length, so time = 300 ÷ 10 = 30 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 240 m long is running at 36 km/h. How much time will it take to cross a pole?
- (A)24 seconds
- (B)48 seconds
- (C)7 seconds
- (D)28 seconds
Show answer and explanation
Correct answer: (A) 24 seconds
Convert the speed to metres per second: 36 × 5/18 = 10 m/s. To cross a pole the train covers its own length, so time = 240 ÷ 10 = 24 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 300 m long is running at 36 km/h. How much time will it take to cross a pole?
- (A)8 seconds
- (B)34 seconds
- (C)27 seconds
- (D)30 seconds
Show answer and explanation
Correct answer: (D) 30 seconds
Convert the speed to metres per second: 36 × 5/18 = 10 m/s. To cross a pole the train covers its own length, so time = 300 ÷ 10 = 30 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 390 m long is running at 108 km/h. How much time will it take to cross a pole?
- (A)4 seconds
- (B)13 seconds
- (C)10 seconds
- (D)17 seconds
Show answer and explanation
Correct answer: (B) 13 seconds
Convert the speed to metres per second: 108 × 5/18 = 30 m/s. To cross a pole the train covers its own length, so time = 390 ÷ 30 = 13 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 425 m long is running at 90 km/h. How much time will it take to cross a pole?
- (A)17 seconds
- (B)5 seconds
- (C)21 seconds
- (D)14 seconds
Show answer and explanation
Correct answer: (A) 17 seconds
Convert the speed to metres per second: 90 × 5/18 = 25 m/s. To cross a pole the train covers its own length, so time = 425 ÷ 25 = 17 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 420 m long is running at 54 km/h. How much time will it take to cross a pole?
- (A)25 seconds
- (B)28 seconds
- (C)8 seconds
- (D)56 seconds
Show answer and explanation
Correct answer: (B) 28 seconds
Convert the speed to metres per second: 54 × 5/18 = 15 m/s. To cross a pole the train covers its own length, so time = 420 ÷ 15 = 28 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 120 m long is running at 36 km/h. How much time will it take to cross a pole?
- (A)12 seconds
- (B)9 seconds
- (C)24 seconds
- (D)3 seconds
Show answer and explanation
Correct answer: (A) 12 seconds
Convert the speed to metres per second: 36 × 5/18 = 10 m/s. To cross a pole the train covers its own length, so time = 120 ÷ 10 = 12 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 460 m long is running at 72 km/h. How much time will it take to cross a pole?
- (A)46 seconds
- (B)23 seconds
- (C)6 seconds
- (D)20 seconds
Show answer and explanation
Correct answer: (B) 23 seconds
Convert the speed to metres per second: 72 × 5/18 = 20 m/s. To cross a pole the train covers its own length, so time = 460 ÷ 20 = 23 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 275 m long is running at 90 km/h. How much time will it take to cross a pole?
- (A)15 seconds
- (B)11 seconds
- (C)3 seconds
- (D)22 seconds
Show answer and explanation
Correct answer: (B) 11 seconds
Convert the speed to metres per second: 90 × 5/18 = 25 m/s. To cross a pole the train covers its own length, so time = 275 ÷ 25 = 11 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 110 m long is running at 36 km/h. How much time will it take to cross a pole?
- (A)22 seconds
- (B)8 seconds
- (C)11 seconds
- (D)3 seconds
Show answer and explanation
Correct answer: (C) 11 seconds
Convert the speed to metres per second: 36 × 5/18 = 10 m/s. To cross a pole the train covers its own length, so time = 110 ÷ 10 = 11 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 225 m long is running at 54 km/h. How much time will it take to cross a pole?
- (A)12 seconds
- (B)15 seconds
- (C)4 seconds
- (D)19 seconds
Show answer and explanation
Correct answer: (B) 15 seconds
Convert the speed to metres per second: 54 × 5/18 = 15 m/s. To cross a pole the train covers its own length, so time = 225 ÷ 15 = 15 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
A train 580 m long is running at 72 km/h. How much time will it take to cross a pole?
- (A)29 seconds
- (B)26 seconds
- (C)33 seconds
- (D)8 seconds
Show answer and explanation
Correct answer: (A) 29 seconds
Convert the speed to metres per second: 72 × 5/18 = 20 m/s. To cross a pole the train covers its own length, so time = 580 ÷ 20 = 29 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
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Frequently asked questions
How many SSC CGL Time, Speed and Distance questions can I practise here?
18 questions — 18 moderate. 15 are shown on this page with answers and explanations, and the practice set draws from all of them.
How should I practise Time, Speed and Distance for SSC CGL?
Read through a few solved questions first to see the method, then take a timed practice set. Afterwards, check which questions you got wrong or spent longest on and redo those before moving on.