SSC GD Quant Questions
37 questions on Quantitative Aptitude for SSC GD. Each comes with the correct answer and a worked explanation.
- Questions
- 37
- Easy
- 17
- Moderate
- 20
Quant topics
Quant questions with solutions
The HCF and LCM of two numbers are 8 and 96 respectively. If one of the numbers is 24, what is the other number?
- (A)40
- (B)24
- (C)4
- (D)32
Show answer and explanation
Correct answer: (D) 32
For any two numbers, product of the numbers = HCF × LCM. So the other number = (8 × 96) ÷ 24 = 768 ÷ 24 = 32.
Shortcut: Other number = HCF × LCM ÷ given number.
The perimeter of a square is 68 cm. What is its area?
- (A)578 cm²
- (B)289 cm²
- (C)136 cm²
- (D)324 cm²
Show answer and explanation
Correct answer: (B) 289 cm²
Each side of the square = perimeter ÷ 4 = 68 ÷ 4 = 17 cm. Area of a square = side² = 17 × 17 = 289 cm².
Shortcut: Area = (perimeter/4)².
The circumference of a circle is 176 cm. What is its area? (Take π = 22/7)
- (A)2552 cm²
- (B)2464 cm²
- (C)1232 cm²
- (D)784 cm²
Show answer and explanation
Correct answer: (B) 2464 cm²
Circumference = 2πr = 176, so r = 176 × 7 ÷ (2 × 22) = 28 cm. Area = πr² = 22/7 × 28 × 28 = 2464 cm².
Shortcut: With π = 22/7, a circumference of 44k gives radius 7k and area 154k².
If 25% of a number is 475, what is 75% of the same number?
- (A)1330
- (B)356.25
- (C)1520
- (D)1425
Show answer and explanation
Correct answer: (D) 1425
25% of the number is 475, so the number is 475 × 100 ÷ 25 = 1900. Now 75% of 1900 = 1900 × 75 ÷ 100 = 1425. Hence the required value is 1425.
Shortcut: Scale directly: 475 × 75/25 = 1425.
The price of an item is first increased by 50% and then decreased by 25%. What is the net percentage change in the price?
- (A)12.5% increase
- (B)37.5% increase
- (C)12.5% decrease
- (D)25% increase
Show answer and explanation
Correct answer: (A) 12.5% increase
Let the original price be 100. After a 50% increase it becomes 150. A 25% decrease on 150 gives 150 × 75 ÷ 100 = 112.5. The net change is 112.5 − 100 = 12.5, i.e. 12.5% increase.
Shortcut: Net % change = a − b − ab/100 = 50 − 25 − 12.5 = 12.5%.
A shopkeeper buys an article for ₹500 and sells it for ₹575. What is the profit percentage?
- (A)13%
- (B)20%
- (C)25%
- (D)15%
Show answer and explanation
Correct answer: (D) 15%
Profit = selling price − cost price = 575 − 500 = 75. Profit percentage is always calculated on the cost price: 75 ÷ 500 × 100 = 15%.
Shortcut: Profit % = (SP − CP)/CP × 100.
The marked price of a watch is ₹2,600. If a discount of 25% is allowed, what is its selling price?
- (A)₹1,950
- (B)₹2,575
- (C)₹3,250
- (D)₹1,820
Show answer and explanation
Correct answer: (A) ₹1,950
Discount = 25% of 2600 = 650. Selling price = marked price − discount = 2600 − 650 = 1950. So the watch is sold for ₹1,950.
Shortcut: SP = MP × (100 − d)/100 = 2600 × 75/100.
What is the simple interest on ₹11,500 at 6% per annum for 3 years?
- (A)₹2,070
- (B)₹13,570
- (C)₹2,415
- (D)₹2,760
Show answer and explanation
Correct answer: (A) ₹2,070
Simple interest = P × R × T ÷ 100 = 11500 × 6 × 3 ÷ 100 = 2070. Therefore the interest earned over 3 years is ₹2,070.
Shortcut: 1% of 11500 is 115; multiply by 6 × 3 = 18.
Find the compound interest on ₹20,000 at 10% per annum for 2 years, compounded annually.
- (A)₹4,100
- (B)₹4,200
- (C)₹4,000
- (D)₹4,400
Show answer and explanation
Correct answer: (B) ₹4,200
Amount after 2 years = 20000 × (1 + 10/100)² = 24200. Compound interest = amount − principal = 24200 − 20000 = 4200. Note that the simple interest for the same period would be only 4000.
Shortcut: For 2 years, effective rate = 2r + r²/100 = 21% of 20000.
The average of 11 numbers is 23. If one number is removed, the average of the remaining numbers becomes 20. What is the removed number?
- (A)23
- (B)42
- (C)53
- (D)64
Show answer and explanation
Correct answer: (C) 53
Sum of all 11 numbers = 11 × 23 = 253. Sum of the remaining 10 numbers = 10 × 20 = 200. The removed number is the difference: 253 − 200 = 53.
Shortcut: Removed number = old average + (n − 1) × (old average − new average) = 23 + 10 × (3).
Two numbers are in the ratio 4 : 5 and their sum is 108. What is the larger number?
- (A)72
- (B)104
- (C)12
- (D)60
Show answer and explanation
Correct answer: (D) 60
Let the numbers be 4x and 5x. Then 4x + 5x = 108, so 9x = 108 and x = 12. The larger number is 5x = 5 × 12 = 60.
Shortcut: Larger number = 5/9 of 108.
Rahul can complete a piece of work in 6 days and Suresh can complete the same work in 12 days. In how many days will they finish it working together?
- (A)3 days
- (B)4 days
- (C)9 days
- (D)6 days
Show answer and explanation
Correct answer: (B) 4 days
Rahul's one-day work = 1/6 and Suresh's one-day work = 1/12. Together they do 1/6 + 1/12 = 18/72 = 1/4 of the work per day, so the work is finished in 4 days.
Shortcut: Days together = (a × b)/(a + b) = 72/18 = 4.
A train 600 m long is running at 72 km/h. How much time will it take to cross a pole?
- (A)30 seconds
- (B)8 seconds
- (C)60 seconds
- (D)34 seconds
Show answer and explanation
Correct answer: (A) 30 seconds
Convert the speed to metres per second: 72 × 5/18 = 20 m/s. To cross a pole the train covers its own length, so time = 600 ÷ 20 = 30 seconds.
Shortcut: km/h × 5/18 = m/s; time = length ÷ speed.
If x + 1/x = 6, what is the value of x² + 1/x²?
- (A)12
- (B)36
- (C)40
- (D)34
Show answer and explanation
Correct answer: (D) 34
Squaring both sides: (x + 1/x)² = x² + 1/x² + 2 = 36. Therefore x² + 1/x² = 36 − 2 = 34.
Shortcut: x² + 1/x² = k² − 2 when x + 1/x = k.
The perimeter of a square is 32 cm. What is its area?
- (A)64 cm²
- (B)128 cm²
- (C)81 cm²
- (D)72 cm²
Show answer and explanation
Correct answer: (A) 64 cm²
Each side of the square = perimeter ÷ 4 = 32 ÷ 4 = 8 cm. Area of a square = side² = 8 × 8 = 64 cm².
Shortcut: Area = (perimeter/4)².
Showing 15 of 37 questions. Start a practice set above to work through the rest.
Frequently asked questions
How many SSC GD Quant questions can I practise here?
37 questions — 17 easy and 20 moderate. 15 are shown on this page with answers and explanations, and the practice set draws from all of them.
How should I practise Quant for SSC GD?
Read through a few solved questions first to see the method, then take a timed practice set. Afterwards, check which questions you got wrong or spent longest on and redo those before moving on.